|
|
| *Resource of HR>>>hr training |
Need help on Acceleration Calculations? |
A car accelerates from a standstill to 60 km/hr in 10.0 seconds. What is its acceleration? A train is accelerating at a rate of 2.0 km/hr/s. If its initial velocity is 20km/hr, what is its velocity after 30 seconds? Equation: a= vf-vi/ t a=velocity vf= final velocity vi=initial velociy t=time 1) First you needto make common units of time. you have a velocity in hours and a change in time in seconds. Either make both in hours or both in seconds to be consistent. Since the SI units for acceleration is m/s^2, we'll go with that. To convert 60 km/hr to m/s, do the following conversion: (60 km / 1 hr)(1000 m / 1 km)(1 hr / 3600 sec) Solving, you get 60 km/hr = 16.67 m/s Since acceleration = change in velcoity / change in time and initial velocity is 0 at time 0, Acceleration = (16.67 - 0)/(10 - 0) = 1.67 m/s^2 ------------------ 2) Rewriting your equation to solve for v_f, you get: v_f = a*t + v_i Again, I would convert to SI units for simplicity: (2 km/hr/s)(1000 m / 1 km)(1 hr / 3600 sec) = 0.56 m/s^2 (20 km/hr)(1000 m / 1 km)(1 hr / 3600 sec) = 5.56 m/s Plugging in your known values, solve for v_f: v_f = (0.56)(30) + 5.56 ----------> v_f = 22.36 m/s ----------------------- Hope this helps You have the equations. Start plugging in the values and DO your homework. (1) v=u+at 60=0+a*10 a=6km/hr/sec (2) v=u+at, v=20+30*2 = 80km/hr vf=v vi=u |
| Tags |
| hr management hr manager hr recruitment hr resources hr software hr training |
Categories--Copyright/IP Policy--Contact Webmaster For personal non-commercial use only. |